x = 'MICHAEL'
x[0] = 'M'
x[-1] = 'L'
x[0:3] = 'MIC'
x[::2] = 'MCAL' # it take every second variable.
x[0:5:2] = 'MCA' # retern every second vaiable till 5 where 5 not enter.
len(x) = 7
x + 'hello' = 'MICHAEL hello'
3*'hello' = 'hello hello hello'
\n # represented new line
\ #represented as backslash
\\ # put backslash in the string
y = x.upper()
z = x.replace('ee', 'dd')
x.find('M')
tuple x=(1,"H", 3, ("D","E")) not mutable
Convert String to List:
x.split()
list x = [1,2,3,4] is mutable
x[0] = "D"
del(x[1])
LIST VS Dictionary
LIST contained index, element
Dic contained key, value
Dictionary = {"key1":1, "key2":2}
dic.keys() // return the keys of dec
dic.values() // return the value of the dec
del(dic[key1]) delete the key with it's value
dic[hello]
set = {"a", "b", "c"}
set.add("n")
set.remove("b")
set1 & set2 = the same element in both of set
set1.union(set2) = all the element in both of sets
set1.issubset(set2)
we can add new list by using x.extend([3,4])
x = (("H","D"),("E","N"))
print(x[0][1])
Output// D
0 Comments:
Post a Comment